Complete Square Calculator

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Complete Square Calculator

This calculator helps you rewrite a quadratic expression in the form a(x-h)^2 + k.

Enter coefficients above to see the completed square form.

Understanding the Complete Square Form

The "complete the square" method is a technique used in algebra to rewrite a quadratic expression of the form ax^2 + bx + c into the vertex form a(x – h)^2 + k. This form is incredibly useful for several reasons:

  • Graphing Quadratics: It directly reveals the vertex of the parabola ((h, k)) and its direction of opening (determined by a).
  • Solving Quadratic Equations: It can simplify the process of finding the roots of a quadratic equation.
  • Finding Maxima/Minima: It easily shows the maximum or minimum value of the quadratic function.

The Math Behind the Calculation

To convert ax^2 + bx + c into a(x – h)^2 + k, we follow these steps:

  1. Factor out 'a': If a is not 1, factor it out from the first two terms: a(x^2 + (b/a)x) + c
  2. Complete the Square for the inner expression: Take half of the coefficient of the x term inside the parenthesis ((b/a)), square it, and add and subtract it *inside* the parenthesis.
    Half of (b/a) is (b / (2a)).
    Squaring it gives (b / (2a))^2 = b^2 / (4a^2).
    So we have: a(x^2 + (b/a)x + b^2 / (4a^2) – b^2 / (4a^2)) + c
  3. Form the perfect square: The first three terms inside the parenthesis now form a perfect square: a((x + b / (2a))^2 – b^2 / (4a^2)) + c
  4. Distribute 'a' and simplify: Distribute a back into the parenthesis and combine the constants. a(x + b / (2a))^2 – a(b^2 / (4a^2)) + c a(x + b / (2a))^2 – b^2 / (4a) + c a(x + b / (2a))^2 + (c – b^2 / (4a))

Comparing this to the target form a(x – h)^2 + k, we can identify:

  • h = -b / (2a)
  • k = c – b^2 / (4a)

Example Calculation

Let's complete the square for the expression 2x^2 + 12x + 10.

  • Here, a = 2, b = 12, c = 10.
  • Step 1: Factor out 'a' (which is 2): 2(x^2 + 6x) + 10
  • Step 2: Half of the x-coefficient (6) is 3. Square it to get 9. Add and subtract 9 inside the parenthesis: 2(x^2 + 6x + 9 – 9) + 10
  • Step 3: Form the perfect square: 2((x + 3)^2 – 9) + 10
  • Step 4: Distribute the 2 and simplify: 2(x + 3)^2 – 18 + 10 2(x + 3)^2 – 8

So, the completed square form is 2(x + 3)^2 – 8. The vertex of this parabola is at (-3, -8).

function calculateCompleteSquare() { var a = parseFloat(document.getElementById("coefficient_a").value); var b = parseFloat(document.getElementById("coefficient_b").value); var c = parseFloat(document.getElementById("coefficient_c").value); var resultDiv = document.getElementById("result"); resultDiv.innerHTML = "; // Clear previous results if (isNaN(a) || isNaN(b) || isNaN(c)) { resultDiv.innerHTML = 'Please enter valid numbers for all coefficients.'; return; } if (a === 0) { resultDiv.innerHTML = 'Coefficient "a" cannot be zero for a quadratic expression.'; return; } // Calculate h and k var h_numerator = -b; var h_denominator = 2 * a; var h = h_numerator / h_denominator; var k_term1 = c; var k_term2_numerator = b * b; var k_term2_denominator = 4 * a; var k = k_term1 – (k_term2_numerator / k_term2_denominator); // Determine the sign for h in the final expression var h_sign = h >= 0 ? "-" : "+"; var h_abs = Math.abs(h); // Format the output string var formulaString = ""; if (a === 1) { formulaString = "x"; } else if (a === -1) { formulaString = "-x"; } else { formulaString = a + "x"; } formulaString += " " + h_sign + " " + h_abs; if (a !== 1) { // Parentheses are only needed if 'a' is not 1 formulaString = "(" + formulaString + ")^2"; } else { formulaString = formulaString + ")^2″; } if (a !== 1) { formulaString = a + " (" + formulaString + ")"; } var finalK = k; var k_sign = finalK >= 0 ? "+" : "-"; var k_abs = Math.abs(finalK); var completedSquareForm = formulaString + " " + k_sign + " " + k_abs; // Display results resultDiv.innerHTML += 'Vertex (h, k): (' + h.toFixed(4) + ', ' + k.toFixed(4) + ')'; resultDiv.innerHTML += 'Completed Square Form:'; resultDiv.innerHTML += " + completedSquareForm + "; // Display the derived formula used resultDiv.innerHTML += '
'; resultDiv.innerHTML += 'Derived formulas:'; resultDiv.innerHTML += 'h = -b / (2a)'; resultDiv.innerHTML += 'k = c – b^2 / (4a)'; resultDiv.innerHTML += '
'; }

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