An Electric Bulb is Rated 60w 240v Calculate Its Resistance

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Electric Bulb Resistance Calculator

function calculateResistance() { var power = parseFloat(document.getElementById("powerRating").value); var voltage = parseFloat(document.getElementById("voltageRating").value); var resultDiv = document.getElementById("result"); if (isNaN(power) || isNaN(voltage) || power <= 0 || voltage <= 0) { resultDiv.innerHTML = "Please enter valid positive numbers for Power and Voltage."; return; } // The formula relating Power (P), Voltage (V), and Resistance (R) is P = V^2 / R. // Rearranging to solve for R, we get R = V^2 / P. var resistance = (voltage * voltage) / power; resultDiv.innerHTML = "The resistance of the electric bulb is: " + resistance.toFixed(2) + " Ohms (Ω)"; }

Understanding Electric Bulb Resistance

Electrical devices, like the humble incandescent light bulb, have a property called resistance. Resistance is a measure of how much a material opposes the flow of electric current. It's a fundamental concept in electrical engineering and is quantified in units called Ohms (symbolized by the Greek letter Omega, Ω).

The power rating of an appliance, such as a 60W light bulb, and its operating voltage, like 240V, are directly related to its resistance. Power (P) is the rate at which energy is transferred or converted. Voltage (V) is the electrical potential difference that drives the current. Resistance (R) impedes this flow.

These three quantities are linked by fundamental electrical laws. For a resistive load like a light bulb, the relationship can be expressed by the formula:

P = V² / R

Where:

  • P is the Power in Watts (W)
  • V is the Voltage in Volts (V)
  • R is the Resistance in Ohms (Ω)

If we want to calculate the resistance of an appliance when its power and voltage ratings are known, we can rearrange this formula to solve for R:

R = V² / P

Using our example of a 60W bulb rated for 240V:

R = (240V)² / 60W

R = 57600 V² / 60 W

R = 960 Ω

Therefore, a 60W light bulb designed to operate at 240V has a resistance of 960 Ohms. This resistance determines how much current will flow through the bulb at its rated voltage, and consequently, how much power it will dissipate as light and heat. Higher resistance means less current flows for a given voltage, resulting in lower power consumption.

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