Rate of Cooling Calculator
Calculate the gradient from your Temperature vs. Time graph.
Calculation Results
* A negative rate indicates temperature is decreasing.
How to Calculate Rate of Cooling from a Graph
Calculating the rate of cooling from a graph is a fundamental skill in physics and chemistry, particularly when studying heat transfer or verifying Newton's Law of Cooling. The graph typically plots Temperature on the vertical axis (y-axis) against Time on the horizontal axis (x-axis).
Understanding the Gradient
The rate of cooling is represented by the gradient (slope) of the temperature-time graph. Since cooling involves a drop in temperature over time, the graph curves downwards, resulting in a negative gradient.
The formula for the average rate of cooling between two points is:
Where:
- T₁ and t₁ are the initial temperature and time.
- T₂ and t₂ are the final temperature and time.
Steps to use this Calculator
- Identify Point 1: Select a starting point on your graph's curve or tangent line. Note the Time ($t_1$) and Temperature ($T_1$).
- Identify Point 2: Select a second point further along the x-axis. Note the Time ($t_2$) and Temperature ($T_2$).
- Input Data: Enter these four values into the calculator above.
- Select Units: Match the units to your graph labels (e.g., Minutes and Celsius).
Average vs. Instantaneous Rate
If you select two points far apart on a curved cooling graph, you are calculating the average rate of cooling over that interval. To find the instantaneous rate of cooling at a specific time, you must draw a tangent line touching the curve at that exact time, pick two points on that straight tangent line, and calculate the gradient using those coordinates.
Why is the result negative?
A negative result confirms that the object is losing heat. For example, a rate of -2.5 °C/min means the object's temperature drops by 2.5 degrees Celsius every minute. In many physics contexts, the "rate of cooling" is often referred to by its magnitude (2.5 °C/min) with the understanding that it represents a loss.