How to Calculate the Flow Rate of a Water Tank
Calculating the flow rate of water draining from a tank is a critical task in fluid mechanics, civil engineering, and even home plumbing projects. Whether you are designing an irrigation system, managing industrial chemical tanks, or simply trying to empty a rain barrel, understanding the physics behind gravity-fed flow is essential.
The Physics: Torricelli's Law
The calculation relies primarily on Torricelli's Law. This theorem states that the speed (velocity) of a fluid flowing out of an orifice under the force of gravity is proportional to the square root of the vertical distance between the water surface and the center of the orifice.
The basic formula for velocity is:
v = √(2 · g · h)
- v = Velocity of the fluid (m/s)
- g = Acceleration due to gravity (9.81 m/s²)
- h = Head of water (height in meters)
Calculating the Actual Flow Rate
While Torricelli's Law gives us the theoretical velocity, real-world scenarios involve friction and turbulence. To account for this, we use the Discharge Coefficient (Cd). We also need to account for the area of the outlet pipe.
The final formula for Flow Rate (Q) is:
Q = Cd · A · √(2 · g · h)
- Q = Flow rate (m³/s)
- Cd = Discharge Coefficient (0.60–0.62 for sharp edges, 0.98 for rounded)
- A = Cross-sectional area of the orifice (m²)
Key Factors Affecting Flow Rate
- Water Height (Head): The higher the water level above the outlet, the greater the pressure, resulting in a faster flow rate. As the tank drains and the height decreases, the flow rate will slow down.
- Orifice Diameter: A larger opening allows more water to pass through. Doubling the diameter actually quadruples the area, significantly increasing flow.
- Orifice Shape: A smooth, rounded nozzle allows water to flow more freely (higher Cd) than a sharp-edged hole cut into a tank wall (lower Cd).
Example Calculation
Imagine you have a water tank with a water level 2 meters above the outlet. The outlet is a pipe with a 50mm diameter. Assuming a standard discharge coefficient of 0.61:
- Velocity (v) = √(2 · 9.81 · 2) ≈ 6.26 m/s
- Area (A) = π · (0.025)² ≈ 0.00196 m²
- Flow Rate (Q) = 0.61 · 0.00196 · 6.26 ≈ 0.00748 m³/s
Converting this to common units, you get approximately 448 Liters per minute.