How to Calculate Rate of Effusion for a Gas

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Rate of Effusion Calculator

Calculate gas effusion rates or molar masses using Graham's Law

Enter exactly 3 known values to calculate the remaining unknown variable. Leave the field you want to find empty.
m/s, mol/s, or mL/s
g/mol
m/s, mol/s, or mL/s
g/mol

How to Calculate Rate of Effusion

The rate at which a gas escapes through a tiny pinhole into a vacuum is known as effusion. This physical property is governed by Graham's Law of Effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

r₁ / r₂ = √(M₂ / M₁)

Where:

  • r₁ = Rate of effusion for Gas A
  • r₂ = Rate of effusion for Gas B
  • M₁ = Molar mass of Gas A (g/mol)
  • M₂ = Molar mass of Gas B (g/mol)

Understanding the Physics

Lighter gas molecules move faster than heavier ones at the same temperature and pressure. Because kinetic energy depends on both mass and velocity (KE = ½mv²), if two gases have the same average kinetic energy (same temperature), the gas with the smaller mass (m) must have a higher velocity (v).

This means a light gas like Helium (4.00 g/mol) will effuse much faster than a heavy gas like Sulfur Hexafluoride (146.06 g/mol).

Example Calculation

Let's say you want to compare the rate of Hydrogen gas (H₂, 2.02 g/mol) to Oxygen gas (O₂, 32.00 g/mol). If Oxygen effuses at 5 mL/s, how fast will Hydrogen effuse?

  1. Identify knowns: M₁ (H₂) = 2.02, M₂ (O₂) = 32.00, r₂ (O₂) = 5.
  2. Set up the ratio: r₁ / 5 = √(32.00 / 2.02).
  3. Calculate the mass ratio: 32.00 / 2.02 ≈ 15.84.
  4. Take the square root: √15.84 ≈ 3.98.
  5. Solve for r₁: r₁ = 5 * 3.98 = 19.9 mL/s.

Hydrogen effuses approximately 4 times faster than Oxygen because it is roughly 16 times lighter.

Common Applications

This calculation is vital in various fields, including:

  • Isotope Separation: Enriching uranium for nuclear fuel relies on the slight difference in effusion rates between U-235 and U-238.
  • Industrial Chemistry: determining molecular weights of unknown gases.
  • Safety Engineering: Estimating how quickly a gas leak might spread in a confined space.
function calculateEffusion() { var r1Input = document.getElementById('rate1').value; var m1Input = document.getElementById('mass1').value; var r2Input = document.getElementById('rate2').value; var m2Input = document.getElementById('mass2').value; var resultDiv = document.getElementById('effusion-result'); resultDiv.style.display = 'block'; resultDiv.style.color = '#333'; resultDiv.style.backgroundColor = '#ebf8ff'; resultDiv.style.borderColor = '#0056b3'; // Parse values, keeping track of which are provided var r1 = r1Input === "" ? null : parseFloat(r1Input); var m1 = m1Input === "" ? null : parseFloat(m1Input); var r2 = r2Input === "" ? null : parseFloat(r2Input); var m2 = m2Input === "" ? null : parseFloat(m2Input); // Count nulls to ensure exactly one is missing var inputs = [r1, m1, r2, m2]; var missingCount = 0; for(var i = 0; i < inputs.length; i++) { if(inputs[i] === null) missingCount++; } if (missingCount !== 1) { resultDiv.innerHTML = "Error: Please enter exactly 3 values and leave 1 empty to calculate."; resultDiv.style.backgroundColor = '#fff5f5'; resultDiv.style.borderColor = '#c53030'; return; } // Validate positive numbers if ((r1 !== null && r1 <= 0) || (m1 !== null && m1 <= 0) || (r2 !== null && r2 <= 0) || (m2 !== null && m2 <= 0)) { resultDiv.innerHTML = "Error: Rates and Molar Masses must be positive numbers greater than zero."; resultDiv.style.backgroundColor = '#fff5f5'; resultDiv.style.borderColor = '#c53030'; return; } var resultValue = 0; var resultText = ""; var formulaStep = ""; // Calculation Logic based on Graham's Law: r1/r2 = sqrt(m2/m1) // Case 1: Find r1 if (r1 === null) { // r1 = r2 * sqrt(m2/m1) var ratio = Math.sqrt(m2 / m1); resultValue = r2 * ratio; resultText = "Rate of Gas A (r₁)"; formulaStep = "r₁ = " + r2 + " × √(" + m2 + " / " + m1 + ")r₁ = " + r2 + " × " + ratio.toFixed(4); } // Case 2: Find r2 else if (r2 === null) { // r2 = r1 / sqrt(m2/m1) var ratio = Math.sqrt(m2 / m1); resultValue = r1 / ratio; resultText = "Rate of Gas B (r₂)"; formulaStep = "r₂ = " + r1 + " / √(" + m2 + " / " + m1 + ")r₂ = " + r1 + " / " + ratio.toFixed(4); } // Case 3: Find m1 else if (m1 === null) { // r1/r2 = sqrt(m2/m1) -> (r1/r2)^2 = m2/m1 -> m1 = m2 / (r1/r2)^2 var rateRatio = r1 / r2; var rateRatioSq = Math.pow(rateRatio, 2); resultValue = m2 / rateRatioSq; resultText = "Molar Mass of Gas A (M₁)"; formulaStep = "M₁ = " + m2 + " / (" + r1 + " / " + r2 + ")²M₁ = " + m2 + " / " + rateRatio.toFixed(4) + "²"; } // Case 4: Find m2 else if (m2 === null) { // r1/r2 = sqrt(m2/m1) -> (r1/r2)^2 = m2/m1 -> m2 = m1 * (r1/r2)^2 var rateRatio = r1 / r2; var rateRatioSq = Math.pow(rateRatio, 2); resultValue = m1 * rateRatioSq; resultText = "Molar Mass of Gas B (M₂)"; formulaStep = "M₂ = " + m1 + " × (" + r1 + " / " + r2 + ")²M₂ = " + m1 + " × " + rateRatio.toFixed(4) + "²"; } // Display Output resultDiv.innerHTML = "
Result: " + resultValue.toFixed(4) + "
" + "
Variable Found: " + resultText + "
" + "
" + "Calculation Steps:" + "Using Graham's Law: r₁/r₂ = √(M₂/M₁)" + formulaStep + "" + "Final Answer: " + resultValue.toFixed(4) + "
"; } function resetEffusion() { document.getElementById('rate1').value = "; document.getElementById('mass1').value = "; document.getElementById('rate2').value = "; document.getElementById('mass2').value = "; document.getElementById('effusion-result').style.display = 'none'; }

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