Graham's Law Effusion Rate Calculator
Understanding Graham's Law of Effusion
Effusion is the process where gas particles pass through a tiny opening into a vacuum or a region of lower pressure. Graham's Law, named after the Scottish chemist Thomas Graham, provides a quantitative relationship between the effusion rate of a gas and its molar mass.
The Physics Behind the Calculation
The core principle of Graham's Law is that at a constant temperature, the kinetic energy of different gases is the same. Because kinetic energy depends on both mass and velocity (KE = ½mv²), lighter molecules must move faster than heavier molecules to maintain the same energy level. Consequently, lighter gases effuse much more rapidly than heavier ones.
How to Calculate the Ratio of Effusion Rates
To find the ratio between two gases, you follow these steps:
- Identify the molar masses (M) of both gases (usually found on the periodic table).
- Divide the molar mass of the second gas (M2) by the molar mass of the first gas (M1).
- Take the square root of that result.
Practical Example
Consider Hydrogen (H2) with a molar mass of 2.02 g/mol and Oxygen (O2) with a molar mass of 32.00 g/mol.
- M1 = 2.02
- M2 = 32.00
- Ratio = √(32.00 / 2.02)
- Ratio = √15.84 ≈ 3.98
This means Hydrogen gas effuses nearly 4 times faster than Oxygen gas under identical conditions.